Just Programming: printf("%d",++*p + ++*str1-32)
#include<stdio.h>. main(). { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); } Answer: M. Explanation: p is pointing to character '\n'.str1 is pointing...
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#include <iostream> #. define MaxN 0x3f3f3f3f #define MinN 0xc0c0c0c0. int main(void) {. printf("%d %d\n",MaxN,MinN); //1061109567, -1061109568 return 0; } #include <stdio.h> #include <iostream...